8/(x^3+5x^2+3x-9)=0

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Solution for 8/(x^3+5x^2+3x-9)=0 equation: 


D( x )

x^3+5*x^2+3*x-9 = 0

x^3+5*x^2+3*x-9 = 0

x^3+5*x^2+3*x-9 = 0

x^3+5*x^2+3*x-9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

x = 1

x^3+5*x^2+3*x-9 = 0

1

x-1

x^2+6*x+9

x^3+5*x^2+3*x-9

x-1

x^2-x^3

6*x^2+3*x-9

6*x-6*x^2

9*x-9

9-9*x

0

x^2+6*x+9 = 0

DELTA = 6^2-(1*4*9)

DELTA = 0

x = -6/(1*2)

x = -3 or x = -3

x in { -3, -3, 1} 

x in (-oo:-3) U (-3:1) U (1:+oo)

8/(x^3+5*x^2+3*x-9) = 0

x^3+5*x^2+3*x-9 = 0

x^3+5*x^2+3*x-9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

x = 1

x^3+5*x^2+3*x-9 = 0

1

x-1

x^2+6*x+9

x^3+5*x^2+3*x-9

x-1

x^2-x^3

6*x^2+3*x-9

6*x-6*x^2

9*x-9

9-9*x

0

x^2+6*x+9 = 0

DELTA = 6^2-(1*4*9)

DELTA = 0

x = -6/(1*2)

x = -3 or x = -3

x in { -3, -3, 1} 

(x+3)^2*(x-1) = 0

8/((x+3)^2*(x-1)) = 0

x belongs to the empty set

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